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<blockquote data-quote="hatedonmostly" data-source="post: 7197051" data-attributes="member: 611322">I was following you until I reached this point; I disagree with this here, if the gain is set to match the preout voltage, the amp will produce 100% of it&#039;s output without overdriving itself (under perfect conditions of course). Example, if you have a deck with 8v preouts, you don&#039;t have to turn the gain up all of the way to get the output from the amp, any further than matching the voltage of the HU will just overdrive the amp.But I have an thought. The amp is rated to put out 1200W, so if we take the equation V*C=P,14.4v * 120A = 1728W80% efficiency, so:1728W * 0.80 = 1382.4WThat&#039;s over what the amp&#039;s power rating is, so if we divide by 14.4 to get the actual amperage it pulls...1382.4W / 14.4v = 96ASo in theory, this theoretical amp should draw 96A of current at the very most under perfect conditions? This, of course, would be on be on a tone and actual musical current draw would be much less</blockquote>

[QUOTE="hatedonmostly, post: 7197051, member: 611322"] I was following you until I reached this point; I disagree with this here, if the gain is set to match the preout voltage, the amp will produce 100% of it's output without overdriving itself (under perfect conditions of course). Example, if you have a deck with 8v preouts, you don't have to turn the gain up all of the way to get the output from the amp, any further than matching the voltage of the HU will just overdrive the amp. But I have an thought. The amp is rated to put out 1200W, so if we take the equation V*C=P, 14.4v * 120A = 1728W 80% efficiency, so: 1728W * 0.80 = 1382.4W That's over what the amp's power rating is, so if we divide by 14.4 to get the actual amperage it pulls... 1382.4W / 14.4v = 96A So in theory, this theoretical amp should draw 96A of current at the very most under perfect conditions? This, of course, would be on be on a tone and actual musical current draw would be much less [/QUOTE]

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