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4 ohm or 2 ohm?
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<blockquote data-quote="Savant" data-source="post: 155949" data-attributes="member: 546108"><p>If I'm understanding this.. it's a mono amp so there is just a left/right output.. correct? So, you have a 4 ohm pair on one set of speaker wires (going to the only outputs of the amp)... then you have a 4 ohm load on the other pair, going to the same outputs?.. Since they are not 'linked' as in all 4 working together somehow, I'd have to think that pusing 4 ohm 'left' and 4 ohm 'right' (left being a pair and right being a pair) you would be running 4 ohm, each pairing getting 1/2 the 4 ohm power.. (the resistence of each pair has no effect on the other pair or the amp.. the amp sees a 4 ohm load on 4 speakers total.. that makes sense?) So, if the amp was 1000 rms mono, each pair would be getting 500 rms, or 250 watts a sub..</p><p></p><p>I believe that's what is happening.. If I'm wrong, would someone PLEASE straighten that out? //content.invisioncic.com/y282845/emoticons/biggrin.gif.d71a5d36fcbab170f2364c9f2e3946cb.gif</p></blockquote><p></p>
[QUOTE="Savant, post: 155949, member: 546108"] If I'm understanding this.. it's a mono amp so there is just a left/right output.. correct? So, you have a 4 ohm pair on one set of speaker wires (going to the only outputs of the amp)... then you have a 4 ohm load on the other pair, going to the same outputs?.. Since they are not 'linked' as in all 4 working together somehow, I'd have to think that pusing 4 ohm 'left' and 4 ohm 'right' (left being a pair and right being a pair) you would be running 4 ohm, each pairing getting 1/2 the 4 ohm power.. (the resistence of each pair has no effect on the other pair or the amp.. the amp sees a 4 ohm load on 4 speakers total.. that makes sense?) So, if the amp was 1000 rms mono, each pair would be getting 500 rms, or 250 watts a sub.. I believe that's what is happening.. If I'm wrong, would someone PLEASE straighten that out? [IMG]//content.invisioncic.com/y282845/emoticons/biggrin.gif.d71a5d36fcbab170f2364c9f2e3946cb.gif[/IMG] [/QUOTE]
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