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<blockquote data-quote="JimJ" data-source="post: 607461" data-attributes="member: 555251">what research? Give me annotations, studies, something.I think you&#039;re trying to say that sound doesn&#039;t propagate well until it reaches a full wavelength (basically the distinction between a near field and far field, at least in RF). The problem with this is that at audio frequencies, they cover such a huge spectrum that specific wavelengths are practically irrelevant. Say, for example, that you have a 50Hz sine wave. That waveform is going to have a full wavelength of:lambda = C/Fwhere C is the speed of light (3x10^8 m/s)F is the frequency in cycles/sec (Hz)comes out to around 22 feet...but these number can vary as much as 56 feet (20Hz) or 14 feet (80Hz). So where does 24 come into play? Besides, what&#039;s the &quot;full effect&quot; of the woofer? If you&#039;re in the driver&#039;s near field, are you getting less than the full effect?</blockquote>

[QUOTE="JimJ, post: 607461, member: 555251"] what research? Give me annotations, studies, something. I think you're trying to say that sound doesn't propagate well until it reaches a full wavelength (basically the distinction between a near field and far field, at least in RF). The problem with this is that at audio frequencies, they cover such a huge spectrum that specific wavelengths are practically irrelevant. Say, for example, that you have a 50Hz sine wave. That waveform is going to have a full wavelength of: lambda = C/F where C is the speed of light (3x10^8 m/s) F is the frequency in cycles/sec (Hz) comes out to around 22 feet...but these number can vary as much as 56 feet (20Hz) or 14 feet (80Hz). So where does 24 come into play? Besides, what's the "full effect" of the woofer? If you're in the driver's near field, are you getting less than the full effect? [/QUOTE]

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