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<blockquote data-quote="ramos" data-source="post: 74885" data-attributes="member: 540858">Let&#039;s see first I hve no idea the size of your alternator. But it should have a sticker on it that says. If nothing else give your local autoparts store a call and ask the size of the oem replacement.Next question there are alot of variables involved in this. So I can only offer you an guestimation //content.invisioncic.com/y282845/emoticons/biggrin.gif.d71a5d36fcbab170f2364c9f2e3946cb.gif Lets see we know the wattage ( 800w ) and we know the voltage of your electrical system. We will use 13v for an average just so we have something to work with.&nbsp; Both of these change dynamicly with the music but we can use these numbers to offer a guess using ohm&#039;s law. I=P/E or Current equals Power in watts divided by Electromotive force in volts. So&nbsp; you have 800w divided by&nbsp; our 13v average&nbsp; gives us&nbsp; 61.5 amp. At 800w of output a perfect amp ( 100% efficient ) would draw 61.5 amps of current. But you have to account for the efficiency of your amp in the equation. That&#039;s why I say this is only a guestimation. I hope helped a little //content.invisioncic.com/y282845/emoticons/smile.gif.1ebc41e1811405b213edfc4622c41e27.gif</blockquote>

[QUOTE="ramos, post: 74885, member: 540858"] Let's see first I hve no idea the size of your alternator. But it should have a sticker on it that says. If nothing else give your local autoparts store a call and ask the size of the oem replacement. Next question there are alot of variables involved in this. So I can only offer you an guestimation [IMG]//content.invisioncic.com/y282845/emoticons/biggrin.gif.d71a5d36fcbab170f2364c9f2e3946cb.gif[/IMG] Lets see we know the wattage ( 800w ) and we know the voltage of your electrical system. We will use 13v for an average just so we have something to work with. Both of these change dynamicly with the music but we can use these numbers to offer a guess using ohm's law. I=P/E or Current equals Power in watts divided by Electromotive force in volts. So you have 800w divided by our 13v average gives us 61.5 amp. At 800w of output a perfect amp ( 100% efficient ) would draw 61.5 amps of current. But you have to account for the efficiency of your amp in the equation. That's why I say this is only a guestimation. I hope helped a little [IMG]//content.invisioncic.com/y282845/emoticons/smile.gif.1ebc41e1811405b213edfc4622c41e27.gif[/IMG] [/QUOTE]

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