Chemistry help

[RandyJ 10+ year member]

Just a quick review. Can someone help me find the electrons?

How many electrons in an atom can have the following designations?

n = 4

5p

6dx2 - y2

2s

This is one thing that's starting to rattle my brain. Thanks.//content.invisioncic.com/y282845/emoticons/smile.gif.1ebc41e1811405b213edfc4622c41e27.gif

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[PhatTonyDeMarco 5,000+ posts]

7.

 

[swimfreak26 10+ year member]

n = 4: I'm not going to help too much on this, but remember that you've got 4 quantum numbers, n, l, m, and ms. l can range from 0 thru (n-1) at integer steps, m can be from -l thru l including 0 in integer steps, and ms can be either alpha (up) or beta (down). Count up the options you've got.

5p: For every p set of orbitals you've got 3 degenerate orbitals, px, py, and pz, all which can house two electrons

6dx2-y2: This is a single orbital from the d set with n = 6. Don't let anything fool you, within any single orbital you can house two electrons. This for example correlates to n=6, l=2, m = x where x is somewhere from -2 thru 2 (I won't get into the energy splitting between "degenerate" orbitals within a set which determines the actual quantum number m)...then all you've got is ms, which can be up or down, so 2.

2s: there is only one degenerate orbital in any given level of s, so you've again got just 2 electrons that can fill it