Hi to all,
This is all Information I myself have gathered from the MECP Installers Guide book.
Alright Here's the Question!
I am trying to figure out how much pull on my alternator I am getting from the amp.
Here is the formula We use to figure this out
I = (Po - n*Po + Po) / V
Now
I = amperes
Po=RMS
n=efficiency
V=voltage
So for me its:
I = (3000 - .8*3000 + 3000) / 13.8
So I do this
3000*.8 and i get 2400
3000-2400=600
600+3000
3600/13.8
260.87 This is my amperage draw correct?
and if I'm correct for everyone else heres an easier equation for this:
I = (2-n)Po/V
So for me this would go
1. 2-.8 =1.2
2. 1.2*3000=3600
3. 3600/13.8
And there we go. 260.87!!!!!
Now, We must remember that Most Class D Amplifiers have a 80% Efficiency Rating and Most Class A/B Amplifiers have a 60-70% efficiency Rating!
