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Reload Thread: 2 same DVC subs in parallel, but on in serie. ( 2+8ohm=2ohms) in paralel??? well it..

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    2 same DVC subs in parallel, but on in serie. ( 2+8ohm=2ohms) in paralel??? well it..

    2 same DVC subs in parallel, but on in serie. ( 2+8ohm=2ohms) in paralel??? well it hurt my amp, or subs any. 2 ohms, i can push 1200w rms mu subs are total of 1400w rms for both. i have a 1 farad cap so i have the power the amp needs.







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    or is it 2.5 ohms

    2+8ohms=10ohms, divided by number of subs(2) = 5, divided by parallel (2) = 2.5
    did i do that right? o will, i can always check it one the ohm meter.2.5 should give me like 1000 watts or so.
    subs are dvc. each with 4 ohm loads, so one can be in series and the other in parallel and wier the subs togeter in parallel.
    yall think this well work the way i want it too??? (even distrabution of power to both subs)?




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    errr what the hell you doin? its figured this way top part is 2*8=16 divide that by 2+8 which is 10- 16/10...... 1.6 ohms but why you mixxin subs?



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    not

    im not mixing subs. just the impedences.




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    that is still mixxing and the higher impedence woofer would be loudest



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    Originally posted by audiolife
    that is still mixxing and the higher impedence woofer would be loudest
    Lowest impedance woofer would be the loudest...




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    depends on if its series or parallel and i thought the same thing till richard clark did the run down lol



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    Originally posted by audiolife
    depends on if its series or parallel and i thought the same thing till richard clark did the run down lol
    Branch circuitry can be easily calculated, but given the question, and how he is wiring it, the 2 ohm will take the brunt of the applied energy...




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