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    Does a component set drop ohm load to 2 ohm?

    easy question.

    if the mid is 4 ohm and the tweet is 4 ohm, does the crossover then present a 2 ohm load or stay at 4 ohm?

    Thanks




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    Re: Does a component set drop ohm load to 2 ohm?

    Quote Originally Posted by m48xhp
    easy question.

    if the mid is 4 ohm and the tweet is 4 ohm, does the crossover then present a 2 ohm load or stay at 4 ohm?

    Thanks
    Easier answer.

    The crossover between the two maintains the 4ohm (or more commonly, 3.3, which is fine).

    Only thing to remember is that generally, components tend to be more power hungry, and would benefit from a good amp regardless like any speaker.




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    Re: Does a component set drop ohm load to 2 ohm?

    my speakers are all 80w rms, and im debating between a 65w rms amp or a 125w rms amp.




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    Re: Does a component set drop ohm load to 2 ohm?

    get the 125w, headroom is always good




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    Re: Does a component set drop ohm load to 2 ohm?

    ID 2omh mids for teh win




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    Re: Does a component set drop ohm load to 2 ohm?

    Quote Originally Posted by m48xhp
    easy question.

    if the mid is 4 ohm and the tweet is 4 ohm, does the crossover then present a 2 ohm load or stay at 4 ohm?

    Thanks
    It would be 4ohm for the frequencies the mid is playing, 4ohm for the frequencies the tweeter is playing....and then right around the crossover point things get a little hairy.

    But overall it would maintain a 4ohm nominal impedance.




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    Re: Does a component set drop ohm load to 2 ohm?

    Around the crossover point, it all depends on the quality of the crossover desing and construction as far as what the impedance will be. The way it is supposed to work is that there is a bit of underlap between the crosover freqs and that both drivers are 3dB down at the crossover point. What the passive filter does is increase its impedance as the frequency moves away from the crossover point. Take the tweeter's high pas filter for example. At the crossover point the tweeter and its filter present twice the nominal impedance of the tweeter alone. As the frequency gets lower, the impedance of the filter gets higher. The midrange works the same way. When you wire the two drivers and their filters in parallel, the rising impedances have little effect on the final impedance "seen" by the amplifier at frequencies outside their passed freq range. Effectively the frequencies are divided between the two drivers and the amp only really "sees" the tweeter at high freqs and the mid at lower freqs.



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