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    brandonloserkid's Avatar
    brandonloserkid is offline audiophile



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    taking consideration for mdf width in box volume calc

    when i type in my calculation for box volume, in ft^3

    its H x W x D \ 1728

    do i anything further to get the internal volume like subtract .75 for each side or something to that nature..

    and also how do i get the volume of a wedge box, since it has 2 depths, and a slope.

    sorry for like 3 questions in one post... any help would be great.. in new to actually building enclosures







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    LoneRanger's Avatar
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    Re: taking consideration for mdf width in box volume calc

    Quote Originally Posted by brandonloserkid
    when i type in my calculation for box volume, in ft^3

    its H x W x D \ 1728

    do i anything further to get the internal volume like subtract .75 for each side or something to that nature..

    and also how do i get the volume of a wedge box, since it has 2 depths, and a slope.

    sorry for like 3 questions in one post... any help would be great.. in new to actually building enclosures
    http://www.eatel.net/~amptech/elecdisc/spboxnew2.htm

    everything you need is right there.....and you don't even have to break out the pen and paper!



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    infrabass's Avatar
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    Re: taking consideration for mdf width in box volume calc

    Why are you supposed divide it 1728 anyways? Whats the reason?




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    TheVanMan's Avatar
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    Re: taking consideration for mdf width in box volume calc

    Quote Originally Posted by infrabass
    Why are you supposed divide it 1728 anyways? Whats the reason?
    To convert from cubic inches to cubic feet.
    (12inches/foot)*(12inches/foot)*(12inches/foot) = 1728cuin/cuft
    Most people prefer to see the box volume in cubic feet.


    Quote Originally Posted by brandonloserkid
    its H x W x D \ 1728

    do i anything further to get the internal volume like subtract .75 for each side or something to that nature..

    and also how do i get the volume of a wedge box, since it has 2 depths, and a slope.

    sorry for like 3 questions in one post... any help would be great.. in new to actually building enclosures
    If it is a single sub enclosure (no divider), then subtract 1.5" from every dimension (assuming your using 3/4" mdf). So you would get [(H-1.5")*(W-1.5")*(D-1.5")]/1728
    If it is a double do the above but also subtract the volume of the divider and then divide by the number of chambers (in the case of the double 2). That would get you cubic feet per chamber.

    Wedge boxes are tricky to get the volume of . First you get the internal volume of the box not including the wedges. This volume is [(H-1.5")*(W-1.5")*(TopD)]/1728.

    Then find the volume of the wedge (right triangle) parts of the box. The internal volume of a wedge is 0.5*(W-0.75")*(H-1.5")*(wedgeD-1.5")/1728 (again assuming 0.75" mdf).
    Last edited by TheVanMan; 10-21-2003 at 04:35 PM.



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    infrabass's Avatar
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    Re: taking consideration for mdf width in box volume calc

    why dont you just convert your H W and D to ft and decimal feet, and then multiply them by each other (assuming its a rectangular type cube)




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    TheVanMan's Avatar
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    Re: taking consideration for mdf width in box volume calc

    Quote Originally Posted by infrabass
    why dont you just convert your H W and D to ft and decimal feet, and then multiply them by each other (assuming its a rectangular type cube)
    You could, it doesn't make a difference. It is just less calculations this way. Three conversions with your and one conversion with mine. :p



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