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    New to Ports

    Okay, so I've been winging it-- but it's time to get edumakated.

    On the Fi website it says "Ported box: 1.8-2.5 cuft @ 28-33Hz" for a 12" Fi Q.

    I was wondering, does that include port displacement? I.E. 1.8-2.5 ft^3 including the port?

    Don't use 'gross' and 'net' 'cause that ***** honestly confuses me.

    Net = Total and gross = Box with out port, right?



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    Re: New to Ports

    The specs given by Fi are after sub and port displacement. So

    1.8-2.5+sub+port = gross

    1.8-2.5 after sub and port = net




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    Re: New to Ports

    Quote Originally Posted by SPY View Post
    The specs given by Fi are after sub and port displacement. So

    1.8-2.5+sub+port = gross

    1.8-2.5 after sub and port = net

    AKA the whole box should be within 1.8-2.5 ft^3?



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    Re: New to Ports

    No, the whole box will be more like 2.0 to 3.0ish depending on sub displacement and port displacement.




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    Re: New to Ports

    Quote Originally Posted by SPY View Post
    No, the whole box will be more like 2.0 to 3.0ish depending on sub displacement and port displacement.

    I was throwing this around:

    Internal: 18"x18"x12" [2.25ft^3], the sub has a .16 displacement...
    With two 2.5" (Diameter) Aeroports.

    I did the math, and they have to be 7" long. I'm going to double-baffle to make it look pretty and make it strong [like bull], does the 7" include from the double baffle?

    I.E. 7" from the first opening to the end, right?


    EDIT:: Cache this-- I just realized my trunk's only 17" high at it's highest point

    Back to the drawing board.

    But an answer to my question would still be awesome



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    Re: New to Ports

    Reply for bump:


    New internal dimensions: 16.5" x 13.5" x 19.25" = ~2.48 ft^3 tuned to 38hz

    DB w/ two 2.5" [Diameter] Aeroports going in 6" starting from the outside of the DB


    Aye or nay?



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    Re: New to Ports

    It's more like 2.28 ft^3 after sub and port displacement.

    so (2) 2.5" Aero's 6.47" long will give you 38hz




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    Re: New to Ports

    How is it 2.28?

    (16.5/12) x (13.5/12) x (19.25/12) = 1.375 x 1.125 x 1.6041 = 2.4814 ft^3 - net.


    As for the port (I got this formula off a Rockford Fosgate PDF Aeroport manual):


    LV = (8466 x R^2 / Vb x Fb^2) - (1.463 x R)

    So...

    LV = (8466 x 1.25^2 / (1.16) x 38^2) - (1.463 x 1.25)
    LV = (13228.125 / 1675.04) - (1.82875)
    LV = (7.89719947) - (1.82875)
    LV = 6.06...etc.

    Am I missing something?

    2.48 for the entire box, -.16 for the sub displacement... and then calculate? I mean, I don't see how I can find the area of the port and subtract it with out finding it's length.
    Last edited by IDSkoT; 04-19-2008 at 01:41 AM.



    Now designing / building boxes.
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