Areoport Box Builders...

[DaGh0st]

i have a few qustions on box building with areoports.
1. How do you Find port displacement?
2. Would you count port displacement if you had them outside the box?
3. would 5 4in or 2 6in be better for 2 15" SX's?
4. If the calculator says 31in in length for the port is that 31 divided by the number of areoports?
Thanks

[SPL140.2]

i have a few qustions on box building with areoports.
1. How do you Find port displacement?
2. Would you count port displacement if you had them outside the box?
3. would 5 4in or 2 6in be better for 2 15" SX's?
4. If the calculator says 31in in length for the port is that 31 divided by the number of areoports?
Thanks

If you put 5 4" aeroports in the calculator and it came up with 31" long, each aeroport will have to be that long Id go with 2 6" aeroports instead 5-4" ones. I went with 2-4" aeroports because it was cheaper than the 1-6". Plus some say they gain with the 6" and some say they lose, so its pretty much up in the air.

[DaGh0st]

any more help?

[nVRuckus]

if its outside the box you dont need displacement because there is none. im not exactly sure on calculating the area of a round port myself

[SPL140.2]

if its outside the box you dont need displacement because there is none. im not exactly sure on calculating the area of a round port myself

This may help

www.memphiscaraudio.com/LiveImages/114/27/DocumentURL.pdf%23search='port%2520displacement%25 20of%2520round%2520port'

[DaGh0st]

link didnt work for me

[MikeyB]

You calculate the port displacement by multiplying the surface area by the length of the port.

[3onDubs]

link didnt work for me

Take off the slash at the end

[InhumanAcura]

are you trying to do a good #, or are you putting together a daily system?

[tRiGgEr]

i have a few qustions on box building with areoports.
1. How do you Find port displacement?
2. Would you count port displacement if you had them outside the box?
3. would 5 4in or 2 6in be better for 2 15" SX's?
4. If the calculator says 31in in length for the port is that 31 divided by the number of areoports?
Thanks

1. Radius^2 x PI x Length = Displacment
2. No.
3. 5 4in ports would give more port surface area (better). But 3 each driver is ideal.
4. 31" for each port.

[3onDubs]

You calculate the port displacement by multiplying the surface area by the length of the port.

Wouldn't the surface area be the area of the circle opening.?

IF that's right, then the displacement of a 4" port that is 12" long would be (pie symbol) x 48.

[tRiGgEr]

Wouldn't the surface area be the area of the circle opening.?

IF that's right, then the displacement of a 4" port that is 12" long would be (pie symbol) x 48.

Basic High School math.

To find the surface area of a circle you multiply the Radius by itself (R^2) then multiply that figure by Pi(3.14).

[3onDubs]

Basic High School math.

To find the surface area of a circle you multiply the Radius by itself (R^2) then multiply that figure by Pi(3.14).

So then the answer would be yes. I was inquiring as to whether "surface area" was refering to the surface area of the cylinder, or the circle opening.

[tRiGgEr]

So then the answer would be yes. I was inquiring as to whether "surface area" was refering to the surface area of the cylinder, or the circle opening.

No.

Your equation for finding the displacment was incorrect. a 4" port 12" long would displace 0.09ft^3.

You do not multiply the Diameter by the length. You first find the surface area using the equation I supplied, then multiply that by the length.

[DaGh0st]

are you trying to do a good #, or are you putting together a daily system?

both it will be in a daily driver but i want to put a nice number up for local comps.
Last year 1st place was 149.x