Can someone just find the measurements of these two angles for me? I forgot everything I learned in algebra.

Thanks a lot.

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- 10-16-2005 #1
## Anyone good at math and want to help me real quick?

Can someone just find the measurements of these two angles for me? I forgot everything I learned in algebra.

Thanks a lot.

- 10-16-2005 #2
## Re: Anyone good at math and want to help me real quick?

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- 10-16-2005 #3
## Re: Anyone good at math and want to help me real quick?

or, if that drawing is to scale, you can simply use a protractor.

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Tw1st3d13 (2 Fi BL 15's)

- 10-16-2005 #4
## Re: Anyone good at math and want to help me real quick?

Cool, thanks a lot man. I didn't realize that there's a right triangle there.

- 10-16-2005 #5
## Re: Anyone good at math and want to help me real quick?

There are the measurements, I forgot how to do the SIN COS TAN. Do you divide the 2 angles then apply SIN to that? Could you do it for me?

Thanks a lot.

- 10-16-2005 #6
## Re: Anyone good at math and want to help me real quick?

both angles should be about 79 degrees

if i remember my math right

sohcahtoa for the win

- 10-16-2005 #7
## Re: Anyone good at math and want to help me real quick?

yup inverse sin(10.5/10.69)=79.18 degrees

- 10-17-2005 #8
## Re: Anyone good at math and want to help me real quick?

Cool, thanks a lot guys

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