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Reload Thread: Ever Wonder the correct procedure for your 1/0ga Crimp Rings?

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    Ever Wonder the correct procedure for your 1/0ga Crimp Rings?

    Well first you need some stuff.

    LARGE bolt cutters
    1/0 ga wire
    1/0 ga crimp terminal
    Propane/butane torch
    Silver Solder
    SHARP knife




    1 volt = [1(kg)(meter^2)] / [(second^3)(ampere)]

    1 watt = 1 joule / second
    1 watt = (1 Newton)(meter) / second
    1 watt = [1 kg/(second^2)] (meter) / second

    simplifying we find:

    1 watt = [1(kg)(meter)] / (second ^3)


    therefore:

    P = (I)(V)

    1 watt = (1 volt)(1ampere)
    1 watt = ( [1(kg)(meter^2)] / [(second^3)(ampere)] )(1 ampere)
    1 watt = [1(kg)(meter^2)] / (second^3)


    And that is WHY Power is in the SI units of Watts. enjoy!




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    Re: Ever Wonder the correct procedure for your 1/0ga Crimp Rings?

    Strip the 1/0 with your sharp knife. I usually make a ring around the wire then connect the cut ring to the end of the piece I want to take off.





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    Re: Ever Wonder the correct procedure for your 1/0ga Crimp Rings?

    slide ring over stripped wire...





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    Re: Ever Wonder the correct procedure for your 1/0ga Crimp Rings?

    I like to use at least 3 main crimps on it with the bolt cutters. Fortunately I was able to make 4. Keep in mind you can do similar with a vice or a hammer or one of those professional impact crimpers.





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    Re: Ever Wonder the correct procedure for your 1/0ga Crimp Rings?

    Fire up the Propane Torch (8.99 at Ace Hardware + 3.29 for butane refilling bottle)





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    Re: Ever Wonder the correct procedure for your 1/0ga Crimp Rings?

    Heat up the entire thing. When the solder just touching the bare metal melts you have a 'hot joint' Keep the flame on the opposite side of the area you are soldering. This ensures you have a "hot joint"

    AFTER SOLDERING




    BEFORE SOLDERING



    Note that the individual wire color changed to silver and that you can see individual strands. That is indicative of a "hot joint" and that the copper has now been tinned and the Crimp ring is now anchored. (Takes a LOT of solder btw)




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    Re: Ever Wonder the correct procedure for your 1/0ga Crimp Rings?

    You call that a knoif? This is a knoif!



    sorry had to!


    How much was that solder?




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    Re: Ever Wonder the correct procedure for your 1/0ga Crimp Rings?





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    Re: Ever Wonder the correct procedure for your 1/0ga Crimp Rings?

    looks good man, blow torches are fun



    MdOiDcEtRaAtToOrR
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    Re: Ever Wonder the correct procedure for your 1/0ga Crimp Rings?

    i want a link to ur cardomain site.... lots of cool stuff in there im sure



    IA FTW!!!
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    Re: Ever Wonder the correct procedure for your 1/0ga Crimp Rings?

    Knife pics coming....lol hehehe






    1 volt = [1(kg)(meter^2)] / [(second^3)(ampere)]

    1 watt = 1 joule / second
    1 watt = (1 Newton)(meter) / second
    1 watt = [1 kg/(second^2)] (meter) / second

    simplifying we find:

    1 watt = [1(kg)(meter)] / (second ^3)


    therefore:

    P = (I)(V)

    1 watt = (1 volt)(1ampere)
    1 watt = ( [1(kg)(meter^2)] / [(second^3)(ampere)] )(1 ampere)
    1 watt = [1(kg)(meter^2)] / (second^3)


    And that is WHY Power is in the SI units of Watts. enjoy!

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    Re: Ever Wonder the correct procedure for your 1/0ga Crimp Rings?

    i know when we sauder copper pipe for plumbing we use flux should you use flux on this can it help ?




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    Re: Ever Wonder the correct procedure for your 1/0ga Crimp Rings?

    screw the knife, ill take that 20




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    Re: Ever Wonder the correct procedure for your 1/0ga Crimp Rings?

    You can use flux, it only helps conduct the heat to the wire, and with a torch you may not need that as much.




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    Re: Ever Wonder the correct procedure for your 1/0ga Crimp Rings?

    Quote Originally Posted by ANeonRider
    You can use flux, it only helps conduct the heat to the wire, and with a torch you may not need that as much.

    exactly, and a butane torch is FUN!!



    1 volt = [1(kg)(meter^2)] / [(second^3)(ampere)]

    1 watt = 1 joule / second
    1 watt = (1 Newton)(meter) / second
    1 watt = [1 kg/(second^2)] (meter) / second

    simplifying we find:

    1 watt = [1(kg)(meter)] / (second ^3)


    therefore:

    P = (I)(V)

    1 watt = (1 volt)(1ampere)
    1 watt = ( [1(kg)(meter^2)] / [(second^3)(ampere)] )(1 ampere)
    1 watt = [1(kg)(meter^2)] / (second^3)


    And that is WHY Power is in the SI units of Watts. enjoy!

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