Well first you need some stuff.
LARGE bolt cutters
1/0 ga wire
1/0 ga crimp terminal
Propane/butane torch
Silver Solder
SHARP knife
Well first you need some stuff.
LARGE bolt cutters
1/0 ga wire
1/0 ga crimp terminal
Propane/butane torch
Silver Solder
SHARP knife
1 volt = [1(kg)(meter^2)] / [(second^3)(ampere)]
1 watt = 1 joule / second
1 watt = (1 Newton)(meter) / second
1 watt = [1 kg/(second^2)] (meter) / second
simplifying we find:
1 watt = [1(kg)(meter)] / (second ^3)
therefore:
P = (I)(V)
1 watt = (1 volt)(1ampere)
1 watt = ( [1(kg)(meter^2)] / [(second^3)(ampere)] )(1 ampere)
1 watt = [1(kg)(meter^2)] / (second^3)
And that is WHY Power is in the SI units of Watts. enjoy!
Strip the 1/0 with your sharp knife. I usually make a ring around the wire then connect the cut ring to the end of the piece I want to take off.
slide ring over stripped wire...
I like to use at least 3 main crimps on it with the bolt cutters. Fortunately I was able to make 4. Keep in mind you can do similar with a vice or a hammer or one of those professional impact crimpers.
Fire up the Propane Torch (8.99 at Ace Hardware + 3.29 for butane refilling bottle)
Heat up the entire thing. When the solder just touching the bare metal melts you have a 'hot joint' Keep the flame on the opposite side of the area you are soldering. This ensures you have a "hot joint"
AFTER SOLDERING
BEFORE SOLDERING
Note that the individual wire color changed to silver and that you can see individual strands. That is indicative of a "hot joint" and that the copper has now been tinned and the Crimp ring is now anchored. (Takes a LOT of solder btw)
looks good man, blow torches are fun
MdOiDcEtRaAtToOrR
1996 Chevrolet Impala SS 14.5 @ 94
1967 Chevrolet Camaro 18.4 @ 74
i want a link to ur cardomain site.... lots of cool stuff in there im sure
IA FTW!!!Team Sundown... what?
Knife pics coming....lol hehehe
1 volt = [1(kg)(meter^2)] / [(second^3)(ampere)]
1 watt = 1 joule / second
1 watt = (1 Newton)(meter) / second
1 watt = [1 kg/(second^2)] (meter) / second
simplifying we find:
1 watt = [1(kg)(meter)] / (second ^3)
therefore:
P = (I)(V)
1 watt = (1 volt)(1ampere)
1 watt = ( [1(kg)(meter^2)] / [(second^3)(ampere)] )(1 ampere)
1 watt = [1(kg)(meter^2)] / (second^3)
And that is WHY Power is in the SI units of Watts. enjoy!
i know when we sauder copper pipe for plumbing we use flux should you use flux on this can it help ?
screw the knife, ill take that 20
You can use flux, it only helps conduct the heat to the wire, and with a torch you may not need that as much.
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Originally Posted by ANeonRider
exactly, and a butane torch is FUN!!
1 volt = [1(kg)(meter^2)] / [(second^3)(ampere)]
1 watt = 1 joule / second
1 watt = (1 Newton)(meter) / second
1 watt = [1 kg/(second^2)] (meter) / second
simplifying we find:
1 watt = [1(kg)(meter)] / (second ^3)
therefore:
P = (I)(V)
1 watt = (1 volt)(1ampere)
1 watt = ( [1(kg)(meter^2)] / [(second^3)(ampere)] )(1 ampere)
1 watt = [1(kg)(meter^2)] / (second^3)
And that is WHY Power is in the SI units of Watts. enjoy!
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