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    supraman1379's Avatar
    supraman1379 is offline Loud 01 Ranger



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    What the difference between the TermLab, and regular sensors, (mic)

    Im going to a comp thats using the TermLab, and im not sure whether or not i want to compete.



    Ride: 2001 Ford Ranger
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    TermLab Mic - 145.6, 146.0, 142.5(mic was messed up)
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    Re: What the difference between the TermLab, and regular sensors, (mic)

    Termlab = harder to get good numbers on. Termlab is more accurate.




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    Bumpin' Yota's Avatar
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    Re: What the difference between the TermLab, and regular sensors, (mic)

    Quote Originally Posted by supraman1379
    Im going to a comp thats using the TermLab, and im not sure whether or not i want to compete.
    Yes you want to!!

    Do NOT miss any opportunity to compete, irrelevant of the mics.

    Be forewarded however, you wont be doing any huge numbers. I struggle to do 155s legal on it with 9kW on 4 subs....



    1 volt = [1(kg)(meter^2)] / [(second^3)(ampere)]

    1 watt = 1 joule / second
    1 watt = (1 Newton)(meter) / second
    1 watt = [1 kg/(second^2)] (meter) / second

    simplifying we find:

    1 watt = [1(kg)(meter)] / (second ^3)


    therefore:

    P = (I)(V)

    1 watt = (1 volt)(1ampere)
    1 watt = ( [1(kg)(meter^2)] / [(second^3)(ampere)] )(1 ampere)
    1 watt = [1(kg)(meter^2)] / (second^3)


    And that is WHY Power is in the SI units of Watts. enjoy!

  4. #4
    saywhat?'s Avatar
    saywhat? is offline satx120, jealous?



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    Re: What the difference between the TermLab, and regular sensors, (mic)

    hey, yota, hes talkin bout the deland comp for meca. wer going eston, i dont care what u say, were both competeing if i get my wires run.




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    Re: What the difference between the TermLab, and regular sensors, (mic)

    get those wires run!!!

    My system is playing, but it must do a 153 or better tonight or I wont be at the volusia county fairgrounds on sat...



    1 volt = [1(kg)(meter^2)] / [(second^3)(ampere)]

    1 watt = 1 joule / second
    1 watt = (1 Newton)(meter) / second
    1 watt = [1 kg/(second^2)] (meter) / second

    simplifying we find:

    1 watt = [1(kg)(meter)] / (second ^3)


    therefore:

    P = (I)(V)

    1 watt = (1 volt)(1ampere)
    1 watt = ( [1(kg)(meter^2)] / [(second^3)(ampere)] )(1 ampere)
    1 watt = [1(kg)(meter^2)] / (second^3)


    And that is WHY Power is in the SI units of Watts. enjoy!

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    saywhat?'s Avatar
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    Re: What the difference between the TermLab, and regular sensors, (mic)

    so did it do that?i hope so, would love to hear a 150+ setup again.




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    Bumpin' Yota's Avatar
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    Re: What the difference between the TermLab, and regular sensors, (mic)

    Quote Originally Posted by saywhat?
    so did it do that?i hope so, would love to hear a 150+ setup again.
    Nope, thus far the best I can get out of the setup is a 151.5 legal @ 43hz....
    ...and at 45hz....strange....

    I havent touched the box however....that is next



    1 volt = [1(kg)(meter^2)] / [(second^3)(ampere)]

    1 watt = 1 joule / second
    1 watt = (1 Newton)(meter) / second
    1 watt = [1 kg/(second^2)] (meter) / second

    simplifying we find:

    1 watt = [1(kg)(meter)] / (second ^3)


    therefore:

    P = (I)(V)

    1 watt = (1 volt)(1ampere)
    1 watt = ( [1(kg)(meter^2)] / [(second^3)(ampere)] )(1 ampere)
    1 watt = [1(kg)(meter^2)] / (second^3)


    And that is WHY Power is in the SI units of Watts. enjoy!

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