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Reload Thread: What do you do when you need to hit 155+ legal in under 30 days??

  1. 07-16-2004 #1
    Bumpin' Yota's Avatar
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    What do you do when you need to hit 155+ legal in under 30 days??

    First you gotta rip out the old system that could only muster a 151.6... (I could have pulled a 153 or so out of it, but that's not loud enough.)

    YOU RIP IT ALL OUT!!!






    1 volt = [1(kg)(meter^2)] / [(second^3)(ampere)]

    1 watt = 1 joule / second
    1 watt = (1 Newton)(meter) / second
    1 watt = [1 kg/(second^2)] (meter) / second

    simplifying we find:

    1 watt = [1(kg)(meter)] / (second ^3)


    therefore:

    P = (I)(V)

    1 watt = (1 volt)(1ampere)
    1 watt = ( [1(kg)(meter^2)] / [(second^3)(ampere)] )(1 ampere)
    1 watt = [1(kg)(meter^2)] / (second^3)


    And that is WHY Power is in the SI units of Watts. enjoy!
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  3. 07-16-2004 #2
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    Re: What do you do when you need to hit 155+ legal in under 30 days??

    gOt PoWeR???




    1 volt = [1(kg)(meter^2)] / [(second^3)(ampere)]

    1 watt = 1 joule / second
    1 watt = (1 Newton)(meter) / second
    1 watt = [1 kg/(second^2)] (meter) / second

    simplifying we find:

    1 watt = [1(kg)(meter)] / (second ^3)


    therefore:

    P = (I)(V)

    1 watt = (1 volt)(1ampere)
    1 watt = ( [1(kg)(meter^2)] / [(second^3)(ampere)] )(1 ampere)
    1 watt = [1(kg)(meter^2)] / (second^3)


    And that is WHY Power is in the SI units of Watts. enjoy!
    Reply With Quote Register To Reply
  4. 07-16-2004 #3
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    Re: What do you do when you need to hit 155+ legal in under 30 days??

    Then you need some dB Dust and some SPL glue



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  5. 07-16-2004 #4
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    Re: What do you do when you need to hit 155+ legal in under 30 days??




    Wall off the your truck.



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  6. 07-16-2004 #5
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    Re: What do you do when you need to hit 155+ legal in under 30 days??

    One must be VAWY VAWY QUIET when one is working on one's system or SPIES will listen in on you and alert the ENEMY!!!

    bE VAWY VAWY QUIET!!


    .



    .



    .



    Sounddomain is being focking gay right now....stay tuned...



    1 volt = [1(kg)(meter^2)] / [(second^3)(ampere)]

    1 watt = 1 joule / second
    1 watt = (1 Newton)(meter) / second
    1 watt = [1 kg/(second^2)] (meter) / second

    simplifying we find:

    1 watt = [1(kg)(meter)] / (second ^3)


    therefore:

    P = (I)(V)

    1 watt = (1 volt)(1ampere)
    1 watt = ( [1(kg)(meter^2)] / [(second^3)(ampere)] )(1 ampere)
    1 watt = [1(kg)(meter^2)] / (second^3)


    And that is WHY Power is in the SI units of Watts. enjoy!
    Reply With Quote Register To Reply
  7. 07-16-2004 #6
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    Re: What do you do when you need to hit 155+ legal in under 30 days??

    Quote Originally Posted by DBfan187



    Wall off the your truck.

    NO walls are allowed!! Street C only.



    1 volt = [1(kg)(meter^2)] / [(second^3)(ampere)]

    1 watt = 1 joule / second
    1 watt = (1 Newton)(meter) / second
    1 watt = [1 kg/(second^2)] (meter) / second

    simplifying we find:

    1 watt = [1(kg)(meter)] / (second ^3)


    therefore:

    P = (I)(V)

    1 watt = (1 volt)(1ampere)
    1 watt = ( [1(kg)(meter^2)] / [(second^3)(ampere)] )(1 ampere)
    1 watt = [1(kg)(meter^2)] / (second^3)


    And that is WHY Power is in the SI units of Watts. enjoy!
    Reply With Quote Register To Reply
  8. 07-16-2004 #7
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    Re: What do you do when you need to hit 155+ legal in under 30 days??

    Quote Originally Posted by Bumpin' Yota
    gOt PoWeR???




    My amps > your amps.

















    Bah, who am I kidding.

    I loathe you.




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  9. 07-16-2004 #8
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    Re: What do you do when you need to hit 155+ legal in under 30 days??

    What the hell is that chicken wire going to do for them amps? time to bust out the big guns.



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  10. 07-16-2004 #9
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    Re: What do you do when you need to hit 155+ legal in under 30 days??

    Quote Originally Posted by mattj
    What the hell is that chicken wire going to do for them amps? time to bust out the big guns.

    That's 2/0




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  11. 07-16-2004 #10
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    Re: What do you do when you need to hit 155+ legal in under 30 days??

    that last pic doesnt work Yota



    MdOiDcEtRaAtToOrR
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    1967 Chevrolet Camaro 18.4 @ 74
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  12. 07-16-2004 #11
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    Re: What do you do when you need to hit 155+ legal in under 30 days??

    Quote Originally Posted by snova031
    That's 2/0
    I know, I was joking.



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  13. 07-16-2004 #12
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    Re: What do you do when you need to hit 155+ legal in under 30 days??

    Quote Originally Posted by Bumpin' Yota
    One must be VAWY VAWY QUIET when one is working on one's system or SPIES will listen in on you and alert the ENEMY!!!

    bE VAWY VAWY QUIET!!


    .



    .



    .



    Sounddomain is being focking gay right now....stay tuned...
    JUST SO YOU SEE IT! :d



    1 volt = [1(kg)(meter^2)] / [(second^3)(ampere)]

    1 watt = 1 joule / second
    1 watt = (1 Newton)(meter) / second
    1 watt = [1 kg/(second^2)] (meter) / second

    simplifying we find:

    1 watt = [1(kg)(meter)] / (second ^3)


    therefore:

    P = (I)(V)

    1 watt = (1 volt)(1ampere)
    1 watt = ( [1(kg)(meter^2)] / [(second^3)(ampere)] )(1 ampere)
    1 watt = [1(kg)(meter^2)] / (second^3)


    And that is WHY Power is in the SI units of Watts. enjoy!
    Reply With Quote Register To Reply
  14. 07-16-2004 #13
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    Re: What do you do when you need to hit 155+ legal in under 30 days??

    Quote Originally Posted by mattj
    I know, I was joking.

    Still got like 25 ft of it, too...also about 30 ft of 1 guage...I love free wire!!!



    sorry for hijacking your thread Yota, but we all know you aren't loud :p




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  15. 07-16-2004 #14
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    Re: What do you do when you need to hit 155+ legal in under 30 days??

    Quote Originally Posted by snova031
    Still got like 25 ft of it, too...also about 30 ft of 1 guage...I love free wire!!!



    sorry for hijacking your thread Yota, but we all know you aren't loud :p

    yEt......

    muah
    muah ha
    mauh haha
    MUAHAHAHAHAHAHHAAHAHAHAHAHAHAHA!!!!



    1 volt = [1(kg)(meter^2)] / [(second^3)(ampere)]

    1 watt = 1 joule / second
    1 watt = (1 Newton)(meter) / second
    1 watt = [1 kg/(second^2)] (meter) / second

    simplifying we find:

    1 watt = [1(kg)(meter)] / (second ^3)


    therefore:

    P = (I)(V)

    1 watt = (1 volt)(1ampere)
    1 watt = ( [1(kg)(meter^2)] / [(second^3)(ampere)] )(1 ampere)
    1 watt = [1(kg)(meter^2)] / (second^3)


    And that is WHY Power is in the SI units of Watts. enjoy!
    Reply With Quote Register To Reply
  16. 07-16-2004 #15
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    Re: What do you do when you need to hit 155+ legal in under 30 days??

    thanks Yota



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    1967 Chevrolet Camaro 18.4 @ 74
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