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saywhat?
03-12-2005, 11:16 AM
okay so outside demension are 19 deep (thats all u need to know)19-1.5 (for wood) leaves 17.5 internal. no, my port wall is flush with the baffle, so i have figured i need 2 inches away from the backwall, which would be15.5+.75 (wall, cuz its flush) which makes it, 16.25 total. now the .75 is like say ur port wall was placed BEHIND ur front baffle....that.75 of your port so ANYWAYS....that gives me 16.25 inches of port....but i need 33 inches. when i turn the port i subtract two from it (radius of port) which would mean i need......14.75 inches of port from the back wall to the END of the port correct? so if i need a 10 inch high port, i would cut the port walls 10x16.25 and 10x14.75????? (the box is 24wx18dx19h) which is like 3.76, woofer displacement is .21 so thats 3.55 and port takes like.....57 or something to that extent, so im aimin for close to 3 cubes NET. its for an RL-p. am i completely off or what?

BASS OUTLAW
03-12-2005, 11:29 AM
man thats very confusing (unclear for me) :(

saywhat?
03-12-2005, 11:53 AM
i explained best i could, im posting a pic in a second.

saywhat?
03-12-2005, 11:54 AM
http://img19.exs.cx/img19/1919/subboxdesign3yv.jpg

saywhat?
03-12-2005, 11:54 AM
that should explain the "port is flush with baffle" idea.