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View Full Version : Can anyone tell what this box is tuned to and how many cubes it is



ChuteBoxe515
11-08-2004, 08:55 PM
I bought some subs and this is the box they came in...http://img76.exs.cx/img76/4867/box4.jpg

ChuteBoxe515
11-08-2004, 08:56 PM
I dont need anything exact, as my measurements werent exact, just something approximate

c0la
11-08-2004, 11:26 PM
Im sure great sounds on mcgalliard should be able to tell u if ur looking for a really quick answer. Well if they are in a good mood they might help u out!

Moe Lester
11-08-2004, 11:29 PM
13" tall, port is 11.25 tall? 7/8" MDF? im not sure how long the port is either, or whether all the measurements are internal or external.

bri487
11-08-2004, 11:36 PM
probably around 4 - 4-1/2 cubes, i didnt figure in the port or anything. the 35"x13"x18" box is 4.7125 ft^3

ChuteBoxe515
11-09-2004, 09:15 AM
those are all external, 3/4 MDF...and the people at GS are *****!

c0la
11-09-2004, 10:51 AM
Yea thats why i wrote if they were in a really good mood the might help, might

pavengmike6
11-09-2004, 11:11 AM
my calculations come up with 3.844, and that is not factoring the port, or basket displacment.

3.679 with 3/4 inch MDF. The first numbers were using 5/8 MDF

ChuteBoxe515
11-09-2004, 12:21 PM
where at in Muncie are you...we should hook up sometime...I am off Oakwood

c0la
11-09-2004, 01:49 PM
Im closer to winchester

tRiGgEr
11-09-2004, 02:02 PM
This is just a rough estimate and no where near accurate because, well your diagram *****.

2.98 after port displacement. Not factoring speaker displacement tuned to 32hz

ChuteBoxe515
11-09-2004, 03:16 PM
my diagram is the ****...it was made with OLD SCHOOL MS PAINT!

tRiGgEr
11-09-2004, 05:50 PM
my diagram is the ****...it was made with OLD SCHOOL MS PAINT!

It was pain tryin to read it.

Where did you get the box. Did the person who sold you the subs make it??? Or is it pre fab.

bri487
11-09-2004, 09:54 PM
those are all external, 3/4 MDF...and the people at GS are *****!that is an estimate for internal volume. correct me if i am wrong, but it is probably closer to 3.5 with the subs in it. the box empty is close to 3.8 or 3.7

LIGHTBEING
11-10-2004, 10:57 AM
Guys, can you explain to me how this is figured out.

Is it wxhxd then divide it by what number? 1728?

and how do you figure out displacement?

tRiGgEr
11-10-2004, 11:06 AM
Guys, can you explain to me how this is figured out.

Is it wxhxd then divide it by what number? 1728?

and how do you figure out displacement?

Box Internal L x W x H = ? then Divide by 1728 to get cubic feet.

Port L x (W+.75) x H = ?

Subtract the port area from the box area.

Then subtract your speakers displacement. Which can be found in the manual.