View Full Version : How is it possible to build a .3 Cube enclosure with this sub?

01-11-2013, 01:01 AM
I have an Infinity Kappa Perfect10 VQ 10" and I am trying to build a legit box for sq. The recommended size box with the low q insert for a sealed box is .3 ft^3 (i have lost the mid q insert :). I am assuming that that is not including the basket displacement which is .072 ft^3. This is a 10" sub with a mounting depth of 6.5", so logically I would not want to build an enclosure with dimensions any smaller than 10x10x8.5 and that is probably still too small but that is already measuring .49 ft^3. How is it possible to build a box to measure .3 ft^3?

Should I just build a bigger box even though it is not an optimal enclosure volume according to Infinity's owners manual?

If its not possible I was thinking of just building a .75 ft^3 box and using the low q Insert although the manual says to use the mid q insert.

(Link to the chart of optimal box sizes for sealed enclosure)
Infinity Kappa Series perfect 10 VQ User Guide (Page 5 of 8) (http://www.manualslib.com/manual/282633/Infinity-Kappa-Series-Perfect-10-Vq.html?page=5#manual)

(Link to speakers specs)
Infinity Kappa Series perfect 10 VQ User Guide (Page 8 of 8) (http://www.manualslib.com/manual/282633/Infinity-Kappa-Series-Perfect-10-Vq.html?page=8#manual)

Thanks for any help!

01-11-2013, 01:15 AM
Put 45's in the corners. Or invert it.