View Full Version : Can someone help me calculate internal volume?

agarabaghi

12-07-2011, 01:25 PM

Wood thickness 0.75

Width at all sections is 13"

All dimensions are outside dimensions

http://img823.imageshack.us/img823/167/boxh.jpg

I need vol before displacement

The box is for a SA10, which im assuming is about 0.12 displacement?

agarabaghi

12-07-2011, 01:29 PM

When i split it into 2 boxes, i get 1.38ft^3

Robert 2001

12-07-2011, 01:58 PM

Actually its 1.5685221 cu ft before sub displacement subtract .12 for sub 1.4485221 cu ft after displacement ir .12 is correct for sub

Robert 2001

12-07-2011, 02:02 PM

LxWxH then divide by 1728 to convert cu in to cubic ft dont forget to subtract wood thickness on all sides

agarabaghi

12-07-2011, 02:04 PM

I finall different recommendations for this sub:

Sundown Sa10

from sundownonly.com

Displacement 0.10 ft^3

Sealed box 0.5 cu. ft.

Ported box 0.75-1.0 cu. ft.

from ssa:

VENTED :

1.25 - 1.5 cubic feet tuned to 30 - 35 Hz

Yields F3 in the mid to high 20s

SEALED :

0.55 cubes for 0.707 Qtc alignment

Yields F3 of 50 Hz

agarabaghi

12-07-2011, 02:11 PM

Ive used multiple calculators and get ~1.4ft^3

OmegaBunny

12-07-2011, 02:44 PM

I get 1.65cu ft before displacement :(

agarabaghi

12-07-2011, 02:47 PM

why is this so hard lol...

im taking 2 boxes:

12.75 x 12 x 13

8.25 x 15 x 13

and putting each into 12v calc:

0.79

0.61

add them up

1.4

subtract .1 for displacement

1.3ft^3...?

Robert 2001

12-07-2011, 03:47 PM

Are u subtracting 3/4 inch .for wall of box on each side. 1.56 before displacement 1.4 after not that .1 of a cube is a big deal but I figured using cu in and converted to cu ft about as accurate as youll get.

Robert 2001

12-07-2011, 04:03 PM

Tune it to 30 hz and call it a day.

agarabaghi

12-07-2011, 04:05 PM

pro-rabbit confirmed it was 1.39ft^3 before displacement, and going by the SA10 .10 displacement spec that would be 1.29ft^3...

Going to try a 3" x 15" aero port for a 30hz tuning will let you know how it sounds.

Robert 2001

12-07-2011, 04:27 PM

Sweet not sure how my numbers got that fat but both figures show your right where you need to b either way. Let us jnow how it turns out.

Robert 2001

12-07-2011, 04:31 PM

I would like to know said formula used by pro rabbit. The above mentioned is the only one I know for cu ft or maybe I hit a key wrong putting it in if he used same formula.

agarabaghi

12-07-2011, 09:40 PM

will do!

Wattser93

12-09-2011, 12:29 AM

[(10.5*11.25*11.5)+(14.25*6.75*11.5)+(0.75*6.75*11. 5)]/(12*12*12) = 1.46 ft^3 before displacement.

Far left rectangle, far right rectangle, airspace you subtracted from the wood thickness in between the two main rectangles that actually exists, divided all by 12^3 to change in^3 to ft^3.

DBBOOM

12-09-2011, 12:49 AM

maTh iz harD