View Full Version : Jmac, help with ft^3 calculations

10-20-2003, 02:37 PM
Hey, i've tried a couple different calculators and i keep getting different numbers as to the cubic feet of the box. If someone else can try and get me a number, that would be sweet

Width: 50"
Height: 20"
Depth 1: 4"
Depth 2: 6"

At one place i got 1.7 cubes, and another i got 2.2 cubes.

10-20-2003, 02:53 PM
Yeah, 3/4" MDF. I figured it was less that 2 cubes too, but that other site said 2.2. Do you think that is enough to port it and still have it sound good?

BTW, why did you use 2 different calculations? Can't you just use one? Oh, and there is another part of the box that the sub is attached to. It's dimensions are

Depth 1-3"
Depth 2-.75"(look in my gallery to understand that, that number is just the thickness of the wood because the top depth is inside the box)

10-20-2003, 05:23 PM
1.5" x 14.5" x 20.75" x 0.5 / 1728 = 0.13059 ft^3

1.81734 + 0.13059 = 1.94793 ft^3

Porting that will be difficult, but achievable ...

Is it even worth porting? And if it is, 35 hz would be good right? What would the port dimensions be.

10-20-2003, 05:47 PM
Is there much room to port off to the side or does it take up the full width of your cabin ?

I was thinking several 2" ports out the top, but that's not looking too good ... :(

No, it'd have to be ported out of the top. That is the only side that isn't blocked:(. What about one long port across the top? You looked at the picture of the box in my gallery right?

10-20-2003, 07:25 PM
Well, i definitely dont want port noise, and there is no way i'm building a different enclosure(at least for now). That design is the biggest box i can fit.

There really is no way to make a long enough port? D*mn.