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Nosferatu333
02-14-2009, 05:18 PM
Sup fellaz,

I have a q-logic dual 10 inch enclosure that measures .65 cubes per sub. I need it to measure .525 per sub (Boston Pro .5's)

I plan on placing 2x4's cut to length to drop down the cubes. I have already figured out the lengths i need to drop it to the desired size.

My question to you guys is if im correct in my logic.

I used the formula to calculate internal volume: HxWxD divided by 1728. I plugged in deminsions of 2x4's until i obtained the difference between .65 and .525. I plan to add that difference in 2x4's in the enclosure to drop the total cubes.

Is this a sound plan. I know it may sound confusing but if there are clarifying questions please ask.

If im incorrect in my thinking please correct me.

Thanks to all in advance.

dropped_mazda
02-14-2009, 05:19 PM
just throw it away and build a good MDF box

DonH
02-14-2009, 06:06 PM
just throw it away and build a good MDF box

x2! sell that ish on craigslist! then make a nice little enclosure

mcsoul
02-14-2009, 08:52 PM
Who knows what that box is tuned to. Though
it is calculable. Just sell it and build one.

Nosferatu333
02-14-2009, 09:13 PM
its a sealed box and its MDF. Its easier to just through some displacement material inside.

azimuth
02-14-2009, 09:16 PM
should be fine. paint the inside with a 5$ can of undercoating.