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samger2
06-26-2008, 07:37 PM
Ok...I'm on a new idea now...I want to build a box that sits flush against the back portion of my rear seat in my Cherokee and fires toward the rear of the jeep...the back seat is angled...but I don't have any tools to determine the degree of angle. Is there anyway I can do this without buying a tool?

mokedaddy
06-26-2008, 07:39 PM
Use math.

samger2
06-26-2008, 08:08 PM
Fair enough. Can you help me to do so? Not sure what the formula is.

Blazin_Jason
06-26-2008, 08:09 PM
Time to bust out the trig. I had to review how to do it, since I've been out of school for so long. Basically take a square and use that to figure out the height to where it is at the back of the seat top. Then measure the distance from that "plum" line to the back of the seat bottom. That should give you a triangle with the height and base. Then you can figure out the hypotenuse easily and go from there.

mlstrass
06-26-2008, 08:11 PM
wedge2 style enclosure. Obviously the angled face will go against the rear seat...

http://www.the12volt.com/caraudio/boxcalcs.asp#wed2

samger2
06-26-2008, 08:45 PM
Ok...my brain is mush.

This box isn't the box I'm using, but has the exact degree of angle that I need. I own this box and it fits perfectly in the angled area I'm dealing with.

http://i82.photobucket.com/albums/j275/samger2/h-121lq20dimensions.jpg

skateboardkid
06-26-2008, 09:01 PM
http://www.ajdesigner.com/phptriangle/right_triangle_pythagorean_theorem_c.php


look like its almost exactly 15 inches long, working on the angle

http://www.csgnetwork.com/righttricalc.html

68 degrees on bottom angle sloping upward
and 21 degrees from top sloping downward
other angle is 90 degrees

these are aproxamations im off by a degree or two..

also you have to subtract the 9 from 14.5 to get the 5.5" that is the length of the bottom triangle to use for calculations

samger2
06-26-2008, 10:06 PM
Actually...I did a google image search for "protractor" then clicked on a pic and held the box up to the picture.

It's a 70 degree angle

silvercookie
06-26-2008, 10:06 PM
why dont you just get a protractor?

samger2
06-26-2008, 10:25 PM
Because it's 9:30pm and I don't feel like leaving the house and I'm trying to do some calculations at my computer before I start building soon.

But I'm sure I'll spend the $1 it takes to get a protractor before I actually start my project.

KoalaZ
06-26-2008, 10:59 PM
http://content.answers.com/main/content/img/cee/g638.gif

Angle A: ~69.25
Angle B: ~20.75

And assuming the box you showed us, side C is about 15.5" long.

maldecido33
06-26-2008, 11:47 PM
Ok...my brain is mush.

This box isn't the box I'm using, but has the exact degree of angle that I need. I own this box and it fits perfectly in the angled area I'm dealing with.

http://i82.photobucket.com/albums/j275/samger2/h-121lq20dimensions.jpg

SohCahToa; Sine(theta)=opposite/hypotenuse, Cosine(theta)=adjacent/hypotenuse, Tangent(theta)=opposite/adjacent.

To find that angle, you divide the height of the triangle (14"), which is our OPPOSITE side from the bottom angle we are measuring, by the distance the slant face covers (it would be your bottom depth minus the top depth, or 5"), which is our ADJACENT side. This quotient is 2.54... . The inverse tangent of this is 1.19 radians, or 68.55 degrees.

Tangent(theta)=14/5.5
arctan(14/5.5)=68.55 degrees

edit: top angle:

tangent(theta)=5.5/14
arctan(5.5/14)=21.45 degrees

the other angle is obviously 90 degrees, and 90 + 21.5 + 68.5 = 180 degrees