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naiku
01-15-2008, 11:53 AM
Can someone help me calculating the volume of a wedge box, its a wedge like this (ignore the dots):

.......... -------
.......... /..........\
.......... /..............\
.......... /..................\
........../......................\
.......... -------------------

This is the side view, the top is 6", bottom is 10" and its 18" wide. The angles on the front and back need to be equal. I think this works out to somewhere around 0.5cf (which is what I am trying to achieve, but I am not certain and want to double check before I decide to start cutting any wood. Its to house a sealed 10" 11Kv.2, mounting depth is 5" I have been searching around online, but can't find a calculator that accepts this shape (and the only ones I can find ask for a partial height, which I have no idea what that is or how to get it)

Thanks.

Edit: So the picture looks like crap, but hopefully someone can get an idea of what I am talking about.

ultimate157
01-15-2008, 01:50 PM
Whats the height.

naiku
01-15-2008, 02:26 PM
Whats the height.

So, yup that would have been a helpful measurement!! Sorry, height needs to be 12"

BrianChia
01-15-2008, 02:32 PM
About 0.65 cf with single layer walls. Subtract approximately 0.1 for the sub. So you are pretty close. No harm in going a little bigger.

Trixter
01-15-2008, 02:32 PM
i get exactly 1cu'....i don't know if these are internal or external dimensions though....

BrianChia
01-15-2008, 02:35 PM
I assumed they were external and that the walls were 3/4". Otherwise it would be a perfect 1.

naiku
01-15-2008, 04:24 PM
Thanks both, those dimensions will be external. So sounds like I am just about right for the box size :D

Now to just get on and put it together! Thanks again.

IDSkoT
01-15-2008, 04:28 PM
For future referance:

http://www.the12volt.com/caraudio/boxcalcs.asp#cyl




EDIT:: I feel dumb. Just realized they don't have a wedge calculator on that site. But, still a good place. :D

ultimate157
01-15-2008, 05:07 PM
(Top depth + bottom depth) / 2. That's the rectangular prism equivalent.

Height x Width x Length (Subtracting 1.5 from each measurement for wood thickness)

Minus sub displacement.

I don't see the problem.