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bob9991
11-19-2007, 12:34 AM
ok i dont know how to find the angles or lengths of these im not very good at math

http://i31.photobucket.com/albums/c393/bopo668/Angle-1.jpg

miker
11-19-2007, 01:28 AM
length = 17.35

What is the angle of the top line, and the far left line...

bob9991
11-19-2007, 01:42 AM
idk that was part of my ?thank so much for answering part of it .but what was the formula you used

Mr Cabinetry
11-19-2007, 01:45 AM
ok i dont know how to find the angles or lengths of these im not very good at math

http://i31.photobucket.com/albums/c393/bopo668/Angle-1.jpg

The angle is 78.4 degree's and the other angle is opposite that:

90 - 78.4 = 11.6 + 90 = 101.6 degree's

bob9991
11-19-2007, 01:48 AM
thanks for the info now for the cutting im looking forward to tomarro

miker
11-19-2007, 01:49 AM
a (squared) + b (squared) = c (squared)

Works with ALL RIGHT triangles...

So, you take the top line minus the bottom one. (gives you base of triangle length) Then you square that, and add it to 17 squared (side of said triangle) then get the square root of that number...

EDIT= how did you do that "cabinetry"???

Mr Cabinetry
11-19-2007, 02:03 AM
a (squared) + b (squared) = c (squared)

Works with ALL RIGHT triangles...

So, you take the top line minus the bottom one. (gives you base of triangle length) Then you square that, and add it to 17 squared (side of said triangle) then get the square root of that number...

EDIT= how did you do that "cabinetry"???