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View Full Version : Anyone good at math and want to help me real quick?



gr3nade
10-16-2005, 03:19 PM
Can someone just find the measurements of these two angles for me? I forgot everything I learned in algebra.

http://img.photobucket.com/albums/v718/gr3nade/box1.jpg

Thanks a lot.

SSS 18734
10-16-2005, 03:28 PM
don't you mean you don't remember anything from geometry?

http://img146.imageshack.us/img146/8092/box11fn.jpg (http://imageshack.us)

You would need to find the following dimensions that I highlighted in red. From there you can use SIN COS & TAN functions on a calculator to figure out the missing dimensions.

SSS 18734
10-16-2005, 03:29 PM
or, if that drawing is to scale, you can simply use a protractor.

gr3nade
10-16-2005, 03:35 PM
Cool, thanks a lot man. I didn't realize that there's a right triangle there.

gr3nade
10-16-2005, 03:53 PM
http://img.photobucket.com/albums/v718/gr3nade/165e6095.jpg
There are the measurements, I forgot how to do the SIN COS TAN. Do you divide the 2 angles then apply SIN to that? Could you do it for me?

Thanks a lot.

maldecido33
10-16-2005, 06:36 PM
both angles should be about 79 degrees

if i remember my math right

sohcahtoa for the win

PatFitz9
10-16-2005, 06:48 PM
yup inverse sin(10.5/10.69)=79.18 degrees

gr3nade
10-17-2005, 10:50 AM
Cool, thanks a lot guys