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1990RANGER
06-28-2005, 09:27 PM
Iím doing calculations to build a box for (2) 15Ē Kicker COMPVRs. This is what I have so far:

(Vb) Internal Dimensions: 11,355.80 in^3
(Fb) Tuning Frequency: 32 Hz
(Av) Port Area (face): 152 in.^2 (4 in. x 19 in.)
(Lv) Port Length: solving for

Then I plugged it into the equation in Georgeís ported box building thread:

-Lv = (Av)*1.84*10^8/[(Vb)*1728*((Fb)/0.159)^2] - 0.823*sqrt(Av)
-Lv = 152*1.84*10^8/[(11,355.80)*1728*(32)/0.159)^2] - 0.823*sqrt(152)
-Lv = -10.11 in.

Is this right, cause I donít think Lv should be negative? Oh, and would I be better off calculating the port wall length for just one chamber and then apply the wall length to both? Cause Iím building 1 port per chamber, so there will be 2 separate ports in total when all is said and done.

Also, the (Av) Port Area measurement above is the combination of both of the separate ports Iím talking about.

Harrison486
06-28-2005, 09:59 PM
I tried learning from Georges post and it didn't work.

I had to learn other ways.

1990RANGER
06-28-2005, 10:50 PM
:(, oh well at least I didn't get too far in the calculations.

cjjackson85
06-28-2005, 10:51 PM
Yeah.