port displacement -- help !!!

[Got Mudd ?]

I guess I am tooo dumb , could someone please help /

I have a 10 inch sub , specs say for ported at 33 hz it needs to be in a .75 cubic foot box with (2) 2" ports that are 20 inches long . sub displacement is .093

could someone please tell me what the port displacement would be ? and would i have any trouble with port noise or should i go with one 4" port ???

[psych0ticnemes1]

<-- not good with round ports, sorry

[tRiGgEr]

Port displacment 0.15ft^3.

And 12.56 square inches of port area should be enough for a 10" Hx2. If you go with a 4" it will have the same port area.

I had a 12" and had 24" of port area. Sounded great with no port noise.

[bcarpenterfhl]

If you go with a 4" it will have the same port area.



*sigh* 2 2" ports do not yield the same port area as a single 4" port.

[tRiGgEr]

*sigh* 2 2" ports do not yield the same port area as a single 4" port.

Whoops. I forgot to multiply 1x1x3.14 lol.

I was using 2x3.14.

So two 2" ports have 6.28 and the 4" port will have 12.56.

Thanks bcarpenter.

Even though you were being an *** about it *sigh*;)

[bcarpenterfhl]

Even though you were being an *** about it *sigh*;)

i was just giving you **** man. all is good.

[tRiGgEr]

i was just giving you **** man. all is good.

Die now :evil:

[Got Mudd ?]

so two 2" vents at 20 inches long = 6.28 cubic inches ??

[bcarpenterfhl]

so two 2" vents at 20 inches long = 6.28 cubic inches ??

yes. but thats an incredibly small port for almost any sub.