Ok, I have gotten many different answers about this. If you have an 500 watt mono amp, and you have 2 subs hooked up to it, is that 500 to each or 250? thanks
Ok, I have gotten many different answers about this. If you have an 500 watt mono amp, and you have 2 subs hooked up to it, is that 500 to each or 250? thanks
250 to each
93 blazer
Panasonic>>>>Orion>>>>Kicker>>>>Pioneer
thanks
yea just take the power divided by the number of subs and that is how much there getting
Alpine CDA-9886
RUX-C701
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JL xr-650csi
JL vr-650cxi
2 8" W7
JL HD750/1
JL HD600/4
2007 Chevy Trailblazer
no problem....anytime:p
93 blazer
Panasonic>>>>Orion>>>>Kicker>>>>Pioneer
is it ever possible say like one wire is pressed in farther than the other and one is getting 350 watts and the other is 150? jsut a idea
does anyone know?
No,
The wire is either making a physical conection or its an open circuit. Wires have such low resistances that you can just assume they're ideal.
As for the subs...look at them as resistors and what do we know about ohms law. When there in series just add the resistance up. parallel its the product of the two subs divided by the sum. This means that the Power for each sub is proportional to the resistance that the subs have. More resistance will have less power.
So having 2 (lets say 4ohm svc) subs wired in *parallel ( sub1llsub2 will have less resistance than them being in series ) But now we run into whether your amp will support a 2ohm load...... sinces its mono it most likely will. Its probably rated at 500W @2ohms anyway. So 500W divided by 2 subs will be 250W a piece.
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why would u wana do that anyway
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