You will be running the amp at a 2 ohms load, therefore it would be sqrt(1000*2) since the BX1500D puts out around 1000W into 2 ohms. What kind of box are you using?
Also, FYI, I am using one dual 4 ohm Type R.
You will be running the amp at a 2 ohms load, therefore it would be sqrt(1000*2) since the BX1500D puts out around 1000W into 2 ohms. What kind of box are you using?
Also, FYI, I am using one dual 4 ohm Type R.
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I am using a sealed box. Each chamber has ~1cu/ft after displacement.
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i got a question. im now runnin a single sx in a sealed box. my gain was set for 2 sx's. i do the math and my voltage for 1 sx at 4 ohms is about the same as it was for 2 sx's at 2 ohms. now i wanted some clarification. the reason i need such a high voltage for 1 sub compared to 2 is due to the impedance right? since there is more resistance at 4 ohms im gonna need more voltage to get to the same spot right? im pretty sure im right i just wanna make sure.
llllllllllllllll Educate yourself and help stop the ignorance.
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4 ohms it puts out 1500 and 2 ohms it puts out 2500. so 2 ohms its 70 volts and 4 ohms its 77 volts.
llllllllllllllll Educate yourself and help stop the ignorance.
llllllllllllllll DEA Judge Francis L Young says...
llllllllllllllll Designing a Ported Box
refs: hazardous0388, snoopdan, karleon, thelow, freezeman_7, imtjnotu, Gebrochen, astroladespl, billabongcr , mustbenu , thunder9500 , 91ser, djdilliodon (6 times), stupify, milenko515, Zeuslicious, Bmoorman05, WaTTsLOk187, too dope 1904, nate2587, rbiele126, denalilvr
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so when i get my second sx back im gonna set my gain to 70.7 volts like i had before right?Originally Posted by Jmac
llllllllllllllll Educate yourself and help stop the ignorance.
llllllllllllllll DEA Judge Francis L Young says...
llllllllllllllll Designing a Ported Box
refs: hazardous0388, snoopdan, karleon, thelow, freezeman_7, imtjnotu, Gebrochen, astroladespl, billabongcr , mustbenu , thunder9500 , 91ser, djdilliodon (6 times), stupify, milenko515, Zeuslicious, Bmoorman05, WaTTsLOk187, too dope 1904, nate2587, rbiele126, denalilvr
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Just leave it where it is, it is still providing the same power, 1250W to each SX.
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This is gonna sound real dumb, I know I'm a noob I'm only working on my 2nd system right now... But what exactly is clipping?
have you searched?
MdOiDcEtRaAtToOrR
1996 Chevrolet Impala SS 14.5 @ 94
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Any recommendations on a multimeter. I have already been to autozone (analog only), Kragen (digital with a scary rotary knob that I have no idea what all the settings were for and Radio Shack where I got the 29 range digital one for $29.99 but I am unsure if I got the right one of if perhaps I could have gotten a better one for the money. Please help. Thanks.
Edit: Okay 2 pages down on a search I found that someone here has the same one as I do so I guess it will do the job.
Last edited by psycho72; 01-25-2005 at 08:43 AM.
Is there any kind of division across channels for bridging? Like sqrt(1 600 * 4) = 80v so 40v per channel or do you do 40v for the bridge 'cause it's bridged? Would it be easier to measure the entire bridge or each channel?
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Just measure the bridge, since that is the way you will be running the amp. And for example, if you have an amp that puts out 400W into 4 ohms bridged..
V = sqrt(400*4) = 40, then you would measure the bridged channels and set the gain to get 40V across them.
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is this correct.
my two id max 12 d2 with the orion 2500d wired at 2ohms = 1700 watts amp watts.
=34volts??
Nope,Originally Posted by bossman032
V = sqrt(1700W X 2 ohms)
V = 58.3V
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thanks much bro.Originally Posted by ANeonRider
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